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Je cherche, par une action, à copier le masque d'un calque sur un masque d'un autre calque... à chaque fois, l'action me crée un autre calque avec ce masque (le cliquer glisser pas faisable non plus par une action...)
Une idée ?
Merci
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Can you upload before/after screenshots of the layers panel? A sample file would also be helpful for testing
You wrote (translated via forum software, so something may have been lost):
copy the mask of one layer on a mask of another layer... Each time, the action creates another layer with this mask
The red text indicates that there is an existing layer that you wish to copy the mask to.
While the text in blue indicates that a new layer should be created.
These points possibly contradict each other, so can you clarify what is actually required?
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Click once on the mask on the layer to make it active. Hold alt key and drag to the desired layer.
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Do you want to ask how to record Photoshop action to copy layer mask from one layer to layer above or another layer or you are asking how to copy mask manually from one layer to another.
For the first case scenario I have idea, it is screenshoted below.
For the second case scenario to manually duplicate mask from one layer to another use @jazz-y suggestion.
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@Bojan Živković, using actions, we can create a copy of the mask in the way i described (in one command). As we can see from the parameters, the mask of another layer is assigned to the current layer. The only condition is that before copying, you need to select the target layer (without a mask).
we can also create a new mask on the target layer and copy the existing mask using the Apply Image command:
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Problem with first option, in my opinion is "Layer 0".
Great tip to use Apply Image but still there is "L" layer what is disadvantage in my opinion because action will always look for layer named "L". My example can be used with any two layers one above another where bottom layer has layer mask regardless of naming convention.
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OK Bonja, Thanks ! The solution with "apply an image" is very effective.
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