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deleting ps-paths automatically

New Here ,
May 17, 2017 May 17, 2017

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Hi, we're using PS CC 2017. Doing lots of images including working paths for retouching purposes we finally want to get rid of those paths if being saved as flat tif. But as far as I know Photoshop only allows to manually select and delete those paths.

 

Is there any workaround to do that automatically with script or Photoshop action.

 

many thanks for any advice!

 

br Christian

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Actions and scripting

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correct answers 1 Correct answer

Community Expert , May 17, 2017 May 17, 2017

It can be done via a Script, but the following would include a selected Shape Layer, so you could either amend the Script or use it after flattening.

 

// 2017, use it at your own risk;

#target photoshop

if (app.documents.length > 0) {

try {activeDocument.pathItems.removeAll()}

catch (e) {}

};

 

Edit: Also see

Path Deletion Script

and maybe post on the Photoshop Scripting Forum.

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Community Expert ,
May 17, 2017 May 17, 2017

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It can be done via a Script, but the following would include a selected Shape Layer, so you could either amend the Script or use it after flattening.

 

// 2017, use it at your own risk;

#target photoshop

if (app.documents.length > 0) {

try {activeDocument.pathItems.removeAll()}

catch (e) {}

};

 

Edit: Also see

Path Deletion Script

and maybe post on the Photoshop Scripting Forum.

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Community Expert ,
Apr 17, 2020 Apr 17, 2020

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"... but the following would include a selected Shape Layer, so you could either amend the Script ..."

 

Oh, how I have tried, without success since this topic thread:

 

Free script: Remove Selected

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Community Beginner ,
Apr 17, 2020 Apr 17, 2020

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this deletes paths only no matter how many or what they are named it doesnt touch layers, if thats what you mean

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Community Expert ,
Apr 17, 2020 Apr 17, 2020

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Have you actually tried the script with a shape layer in the file?

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Community Beginner ,
Apr 18, 2020 Apr 18, 2020

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do you want to keep the shape layer and shape layer path and delete all other paths?

I will try to make it do that if that is what your looking for, or do you want to keep the shape layer with no path? not sure how to do that.

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Community Beginner ,
Apr 18, 2020 Apr 18, 2020

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I just revised this and it keeps all layers including the shape layer and shape layer path but deletes all other paths. I just added a command to turn off all layers in photoshop, run the path deletion part of the script and then turn all layers back on and then save.

 

on open fileList

tell application "Adobe Photoshop CC 2018"

activate

repeat with thisFile in fileList

open thisFile showing dialogs never

try

set myDoc to current document

end try

tell application "System Events" to tell process "Adobe Photoshop CC 2018"

set frontmost to true

keystroke "a" using {option down, command down}

keystroke "," using {command down}

end tell

tell myDoc

repeat while first path item exists

if first path item exists then

delete first path item

end if

end repeat

tell application "Adobe Photoshop CC 2018"

activate

tell application "System Events" to tell process "Adobe Photoshop CC 2018"

set frontmost to true

keystroke "," using {command down}

end tell

end tell

close saving yes

end tell

end repeat

end tell

end open

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Community Expert ,
Apr 18, 2020 Apr 18, 2020

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"I just added a command to turn off all layers in photoshop, run the path deletion part of the script and then turn all layers back on and then save."

 

Thank you stevef55565652 that is a very clever idea!

 

Although JS can't send keystrokes, I can emulate these steps using menu calls or script listener code.

 

I see two small issues, it would be better if they were overcome... The initial layer visibility is altered and initial layer selections are altered. So now all I need to do is find out how to capture and restore the initial layer array visibility and selected/targeted layers so that the original document layers are not affected after removing all non-clipping paths (for example) while retaining shape layers.

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Community Expert ,
Apr 18, 2020 Apr 18, 2020

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"do you want to keep the shape layer and shape layer path and delete all other paths?"

 

Yes, however, I would like the ability to include/exclude different path kinds (clipping, normal, work) while retaining shape layers.

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Community Expert ,
Apr 18, 2020 Apr 18, 2020

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Stephen, could you try this: 

// 2020, use it at your own risk;
if (app.documents.length > 0) {
////// deselect layers //////
var desc2 = new ActionDescriptor();
var ref1 = new ActionReference();
ref1.putEnumerated( stringIDToTypeID( "layer" ), stringIDToTypeID( "ordinal" ), stringIDToTypeID( "targetEnum" ) );
desc2.putReference( stringIDToTypeID( "null" ), ref1 );
executeAction( stringIDToTypeID( "selectNoLayers" ), desc2, DialogModes.NO );
////// get paths //////
var ref = new ActionReference();
ref.putEnumerated( charIDToTypeID("Dcmn"), charIDToTypeID("Ordn"), charIDToTypeID("Trgt") ); 
var docDesc = executeActionGet(ref);
if (docDesc.hasKey(stringIDToTypeID("numberOfPaths")) == true) {
var theNumber = docDesc.getInteger(stringIDToTypeID("numberOfPaths"));
var theArray = new Array;
////// work through paths //////
for (var m = 0; m < theNumber+1; m++) {
try {
var ref = new ActionReference();
ref.putIndex( stringIDToTypeID( "path" ), m);
var pathDesc = executeActionGet(ref);
var theName = pathDesc.getString(stringIDToTypeID("pathName"));
var theKind = pathDesc.getEnumerationValue(stringIDToTypeID("kind"));
var theIndex = pathDesc.getInteger(stringIDToTypeID("itemIndex"));
theArray.push([theName, theKind, theIndex]);
} catch (e) {}
};
////// delete //////
for (var n = theNumber-1; n >= 0; n--) {
var desc4 = new ActionDescriptor();
var ref2 = new ActionReference();
ref2.putIndex( stringIDToTypeID( "path" ), theArray[n][2] );
desc4.putReference( stringIDToTypeID( "null" ), ref2 );
executeAction( stringIDToTypeID( "delete" ), desc4, DialogModes.NO );
};
};
};

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Community Expert ,
Apr 18, 2020 Apr 18, 2020

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thank you c_pfaffenbichler for the code! It does indeed work, however, as I mentioned in the other referenced topic I have been looking for fine control over which path types are removed/retained. This could be for many paths in a single file or perhaps performed on many files in a batch.

 

The challenge is having the ability to:

 

i) Include/Exclude a particular PathKind (CLIPPINGPATH or NORMALPATH or WORKPATH)

ii) Not removing shape layers

 

Perhaps the most common "cleanup" would be to provide a client with a duped final file (layered or flattened) that contained a clipping path – so all saved normal paths and work paths would be removed, while clipping paths and shape layers would be retained.

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Community Expert ,
Apr 19, 2020 Apr 19, 2020

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I was being lazy and just had the Script deselect all Layers so that Vector Masks and Shape Layers would simply not be listed among the Paths … 

Here is a version that would not delete the Clipping Path, the ID for Work Path is in a comment. 

// 2020, use it at your own risk;
if (app.documents.length > 0) {
////// deselect layers //////
var desc2 = new ActionDescriptor();
var ref1 = new ActionReference();
ref1.putEnumerated( stringIDToTypeID( "layer" ), stringIDToTypeID( "ordinal" ), stringIDToTypeID( "targetEnum" ) );
desc2.putReference( stringIDToTypeID( "null" ), ref1 );
executeAction( stringIDToTypeID( "selectNoLayers" ), desc2, DialogModes.NO );
////// get paths //////
var ref = new ActionReference();
ref.putEnumerated( charIDToTypeID("Dcmn"), charIDToTypeID("Ordn"), charIDToTypeID("Trgt") ); 
var docDesc = executeActionGet(ref);
if (docDesc.hasKey(stringIDToTypeID("numberOfPaths")) == true) {
var theNumber = docDesc.getInteger(stringIDToTypeID("numberOfPaths"));
var theArray = new Array;
////// work through paths //////
for (var m = 0; m < theNumber+1; m++) {
try {
var ref = new ActionReference();
ref.putIndex( stringIDToTypeID( "path" ), m);
var pathDesc = executeActionGet(ref);
var theName = pathDesc.getString(stringIDToTypeID("pathName"));
var theKind = pathDesc.getEnumerationValue(stringIDToTypeID("kind"));
var theIndex = pathDesc.getInteger(stringIDToTypeID("itemIndex"));
theArray.push([theName, theKind, theIndex]);
} catch (e) {}
};
alert (theArray.join("\n"));
////// delete //////
for (var n = theNumber-1; n >= 0; n--) {
// work paths 1467116368;
if (theArray[n][1] != 1131180112) {
var desc4 = new ActionDescriptor();
var ref2 = new ActionReference();
ref2.putIndex( stringIDToTypeID( "path" ), theArray[n][2] );
desc4.putReference( stringIDToTypeID( "null" ), ref2 );
executeAction( stringIDToTypeID( "delete" ), desc4, DialogModes.NO );
};
};
};
};

 

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Community Expert ,
Apr 19, 2020 Apr 19, 2020

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Thank you c_pfaffenbichler that was what I have been trying to achieve with standard code!

 

phEnumNormalPath -> 1316121936 -> "NrmP" normalPath
phEnumWorkPath -> 1467116368 -> "WrkP" workPathIndex
phClassClippingPath -> 1131180112 -> "ClpP" clippingPathEPS

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Community Expert ,
Apr 20, 2020 Apr 20, 2020

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I have had to incorporate an "if/else" routine to check for flattened and layered content in order to run two sets of code – one for a flattened image with paths and another for layered images with paths.

 

Some things that I have learnt about scripting from this topic thread:

 

1) Test with a flattened image, as results may differ from a layered image

2) Test with a layered image, as results may differ from a flattened image

3) Test with different layers and layer sets visible as results may vary

4) Test with different layers and layer sets selected as results may vary

5) Test with no layers selected as results may vary

6) c_pfaffenbichler must be like Neo from the Matrix movie series, seeing the world in hidden code! :]

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Community Expert ,
Apr 20, 2020 Apr 20, 2020

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Oh, no, I am still very much uncomfortable with AM code. 

And what I can achieve with it is owed in large parts to xbytor, Paul Riggott and Michael L Hale (and other regulars at the old Photoshop Scripting Forum) a couple years back. 

 

I am not trying to downplay the efforts and achievements of others by not mentioning them by name, but with those three it happened that they were very active when I started looking into Photoshop Scripting myself. 

Their knowledge and their willingness to share it with others were impressive and a great boon to the Forum. 

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Community Expert ,
Apr 22, 2020 Apr 22, 2020

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Thank you c_pfaffenbichler your code has helped me update a project that has been stalled for a couple of years! 

Bulk Remove All Selected Items 2020.png

Free script: Remove Selected

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Community Beginner ,
Apr 17, 2020 Apr 17, 2020

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This is the first script that I have posted. I have been helped by many other people on this site so I thought I would put this one on.

This is a applescript droplet that deletes all paths and saves the image. Change the tell appplication

"Adobe Photoshop CC 2018" to whatever version of photoshop your using.

This script deletes the first path item while the first path item exists and repeats until there is no first path items.

I had to delete all the paths from the images that I was retouching for work so I made this. It's just pieces of other scripts I found, but seems to work well for me.

Copy the script into Script Editor and export as an application to your desktop and uncheck all 3 options before saving. You can drop your images on it and the paths will be deleted.

 

on open fileList

tell application "Adobe Photoshop CC 2018"

activate

repeat with thisFile in fileList

open thisFile showing dialogs never

try

set myDoc to current document

end try

tell myDoc

repeat while first path item exists

if first path item exists then

delete first path item

end if

end repeat

close saving yes

end tell

end repeat

end tell

end open

 

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Community Expert ,
Apr 18, 2020 Apr 18, 2020

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Hi stevef55565652 thank you for sharing your code and bumping this topic!

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LEGEND ,
Apr 22, 2020 Apr 22, 2020

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Moderator label this thread as 'Actions and scripting'.

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Community Expert ,
Jan 27, 2023 Jan 27, 2023

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LATEST

I stumbled over this old topic and thought that I should update it with the current code that I use.

 

removeAllClipPaths()

function removeAllClipPaths() {
    // Stephen Marsh, 2022
    // Hide the active layer to ensure that vector shape paths are not inadvertently removed!
    var docPaths = activeDocument.pathItems;
    if (app.activeDocument.activeLayer.isBackgroundLayer) {
        clipPathRemover();
    } else {
        if (activeDocument.activeLayer.visible == false) {
            clipPathRemover();
        } else {
            activeDocument.activeLayer.visible = false;
            clipPathRemover();
            activeDocument.activeLayer.visible = true;
        }
    }

    function clipPathRemover() {
        for (i = docPaths.length - 1; i > -1; i--) {
            thePaths = docPaths[i];
            if (thePaths.kind == "PathKind.CLIPPINGPATH") {
                thePaths.remove()
            }
        }
    }
}

 

removeAllNormalPaths();

function removeAllNormalPaths() {
    // Stephen Marsh, 2022
    // Hide the active layer to ensure that vector shape paths are not inadvertently removed!
    var docPaths = activeDocument.pathItems;
    if (app.activeDocument.activeLayer.isBackgroundLayer) {
        normalPathRemover();
    } else {
        if (activeDocument.activeLayer.visible == false) {
            normalPathRemover();
        } else {
            activeDocument.activeLayer.visible = false;
            normalPathRemover();
            activeDocument.activeLayer.visible = true;
        }
    }

    function normalPathRemover() {
        for (i = docPaths.length - 1; i > -1; i--) {
            thePaths = docPaths[i];
            if (thePaths.kind == "PathKind.NORMALPATH") {
                thePaths.remove()
            }
        }
    }
}

 

removeAllWorkPaths();

function removeAllWorkPaths() {
    // Stephen Marsh, 2022
    // Hide the active layer to ensure that vector shape paths are not inadvertently removed!
    var docPaths = activeDocument.pathItems;
    if (app.activeDocument.activeLayer.isBackgroundLayer) {
        workPathRemover();
    } else {
        if (activeDocument.activeLayer.visible == false) {
            workPathRemover();
        } else {
            activeDocument.activeLayer.visible = false;
            workPathRemover();
            activeDocument.activeLayer.visible = true;
        }
    }

    function workPathRemover() {
        for (i = docPaths.length - 1; i > -1; i--) {
            thePaths = docPaths[i];
            if (thePaths.kind == "PathKind.WORKPATH") {
                thePaths.remove()
            }
        }
    }
}

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