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Matching Reds using multiple images

New Here ,
Mar 12, 2021 Mar 12, 2021

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I'm relatively new to Photoshop, but have been able to find the answers to most of my issues on YouTube or Google to this point.

I'm trying to create a graphic using multiple action photos from different sports. So I took each photo and individually isolated the reds, while making the rest of the image black and white.

But my issue is when I bring them altogther into 1 graphic, the reds are clearly multiple shades and it doesn't look good.

I'm trying to have all the reds be Pantone 200 or #C32132. 

Just wondering anyone might be able to help me accomplish this? I have no issue watching tutorial videos or reading a manual. Just can't seem to find anything online to match what I'm looking for.

I've attached a screenshot to show you what I'm talking about. Thanks!

 

Screen Shot 2021-03-12 at 3.36.17 PM.png

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Adobe
Community Expert ,
Mar 12, 2021 Mar 12, 2021

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Screen Shot 2021-03-12 at 4.06.01 PM.png

In order to be most helpful we would need to see how you “individually isolated the reds.”  A view of the Layers panels would probably show it very well.

 

That said, I took your composite image into Lab where the mask was easily made from a copy of the  a  channel. (The Before and After are shown above.)

 

The PMS color you specified consists of Lab values L42 a66 b34. It was obtained on a duplicate layer of the image and then the mask was added.

 

As the Curves show, the adjustment to reach those values was very modest. In addition, the comparison of the side-by-side Before and After images show that your attempt to match the reds was well done.

 

The images are very similar in color.  The variation you see in the reds in your composite image is the result of differences in tone, not color.  

 

Since the red areas are not flat color,  a modification of the tone in each red area would have to be made individually in parts of the L channel. Often you risk getting a faked result since the images vary in tone level and local contrast. I suggest you use the result you presented here.  Good job.

 

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