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SuwekongHilaw
Inspiring
April 25, 2024
Answered

How to get the currently opened bin?

  • April 25, 2024
  • 1 reply
  • 1370 views

By this, I mean when you double-click on a bin and you are inside it.

I need a script that imports a file in another specified bin while respecting the current active bin as its parent bin.

 

While inside a bin, simply using app.project.importFiles(<path>) without specifying a ProjectItem would respect the current active bin. So far so good. However, if I need to create a new bin and import the file inside it, then I have to create the new bin first inside the current bin so I can pass that ProjectItem to importFiles().

 

The problem is that I can't find a way to get the ProjectItem of the currently opened bin. What is a good way to achieve this?

    This topic has been closed for replies.
    Correct answer SuwekongHilaw

    I tested using this code:

      var viewIDs = app.getProjectViewIDs();
      var viewSelection = app.getProjectViewSelection(viewIDs[0]);
     
    Result:
    Case #1: Selected/highlighted 2 bins - viewSelection contains 2 items
    Case #2: Entered/opened a bin, where there's another bin inside - viewSelection contains only one items, and that is of the currently opened bin
    Case #3: While still in the opened bin, select/highlight the bin inside it - same as above, viewSelection still contains the currently opened bin item
     
    I guess I can make a workaround through Case #2, but this feels like a hack to me.

    1 reply

    D
    Adobe Employee
    Dan McSweeney
    Adobe Employee
    April 25, 2024

    Hi SuwekongHilaw,

    "the currently open bin" is not reflected in the API - and I don't think you need it.

    In the sample panel on github, you'll find 

    var viewIDs = app.getProjectViewIDs();

    at https://github.com/Adobe-CEP/Samples/blob/9efca02ea88ad32a8c22571f5ffe2407ae732cd8/PProPanel/jsx/PPRO/Premiere.jsx#L1954 

    this view gives you the project

    Then you can use getInsertionBin()

    Create containing bin within insertion bin

    app.project.rootItem.createBin(containing bin)
    then importFiles(), specifying new containing bin as destination

     

    I hope that's helpful. Play with it a bit, then post back with other questions.

    -Dan

    S
    SuwekongHilawAuthorCorrect answer
    Inspiring
    April 26, 2024

    I tested using this code:

      var viewIDs = app.getProjectViewIDs();
      var viewSelection = app.getProjectViewSelection(viewIDs[0]);
     
    Result:
    Case #1: Selected/highlighted 2 bins - viewSelection contains 2 items
    Case #2: Entered/opened a bin, where there's another bin inside - viewSelection contains only one items, and that is of the currently opened bin
    Case #3: While still in the opened bin, select/highlight the bin inside it - same as above, viewSelection still contains the currently opened bin item
     
    I guess I can make a workaround through Case #2, but this feels like a hack to me.
    Bruce Bullis
    Bruce Bullis
    Legend
    April 29, 2024

    In case #3, getInsertionBin() returns the selected bin, viewSelection[0] returns the open bin. If I unselect the bin inside the open bin, both methods return the open bin.

     

    I tried out how import behaves in Premiere by default, and it looks like it always respects the selected bin, otherwise, the opened bin. I didn't think I should consider the selected bin as the insertion point, but now I believe I should to be consistent with Premiere's behaviour.

     

    So it looks like app.project.getInsertionBin() is all that I need after all. Thank you for your patience in answering my questions!


    You may need the ViewID stuff, to figure out which open project's insertion bin to get. 🙂


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