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Participant
July 9, 2018
Answered

Negating an image out of a photograph

  • July 9, 2018
  • 4 replies
  • 757 views

I have recently purchased a photo scanner.  While scanning some images, I noticed that the camera is reflecting off of the image.  I figured that I could scan an image of just a blank sheet of photo paper and get the image of the camera.  I would like to negate the image of the camera.  I figured that I could just change the layer blending mode to multiply, but it didn't work.  It looks like a double-exposure, but I have a clean photo that I would like to remove. Anyone know how to do this?

This is a picture of my daughter.  The camera reflection can be seen in the center and throughout.  Like I said, I have an image of nothing but the camera.

I appreciate any help that I can get.

Matthew

This topic has been closed for replies.
Correct answer davescm

Have you got a scan of a plain black image on reflective paper? You may then get close with subtract - but you would still need to finish off with manual retouching.

Personally I would give up on that scanner for prints and either photograph them with a digital camera or use a flatbed scanner.

One last thing you could try - if the box on your scanner  opens up you could coat the inside with black felt.

Dave

4 replies

NunuNeveuAuthor
Participant
July 9, 2018

I was hoping to use DIFFERENCE in order to remove the reflection.  Didn't quite do what I had hoped.  I just got a bee in my bonnet about scanning all of the photographs of my kids in the event that something happens to them.  Everything that I have found online is assuming that the picture has come from taking a photograph of a "whatever" and all the replies have about legal issues and stealing art.  I have taken all of these pictures and now I am simply trying to make myself digital copies.  The pictures are all about 20 years old and I would like to give copies of them to the kids after I assemble them.

Per Berntsen
Community Expert
Community Expert
July 9, 2018

I'm not familiar with this type of scanner, which seems to a copy stand with camera built into a box.

But if you use a regular flatbed scanner instead, there shouldn't be any problems with reflections.

NunuNeveuAuthor
Participant
July 9, 2018

The problem is this.  The scanner is an Ion Pics 2 SD photograph/negative/slide scanner.  It is a box about 8 inches by 7 inches by 5 inches tall. It has a 5MP camera inside the box with lights and the whole works.  Problem is, the a lot of the photographs are highly reflective.  This puts a camera reflection on the image.  I have attempted to create just the reflection image of the camera by using a blank piece of photo paper, but the camera adjusts the lighting.  Here is the image of the camera.  The horizontal lines, well, I'll just have to remove them manually.

D Fosse
Community Expert
Community Expert
July 9, 2018

As above - what does a camera have to do with a scanned image? If the camera reflection is in the original image that's a completely different problem.

Assuming this is a straight reflection, this is extremely difficult to remove afterwards, much more difficult than you think. An image of the camera in question is no help.

Do it again, and set up the lighting properly this time: two point light sources at 45 degrees angle to the sides. If you want to kill reflections completely in highly reflective surfaces like glass, you need to use cross-polarized lighting.

davescm
Community Expert
Community Expert
July 9, 2018

I was thinking you may be able to do this with a scan of a black sheet, then subtracting the reflection using the same principle as a dark image in long exposure photography. Hence I asked to see the blank scan.

However, as others have indicated, it may be far quicker to just rescan.

Dave

davescm
Community Expert
Community Expert
July 9, 2018

Hi

Can you post the camera image at the same size.

Dave

c.pfaffenbichler
Community Expert
Community Expert
July 9, 2018

What seems strange to me is what the camera has to do with the digital image created by a scanner.