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M
Marketing310340444dbt
Participant
July 13, 2023
해결됨

Search for a certain letter in the last line of a text with always different numbers of lines

  • July 13, 2023
  • 1 답변
  • 364 조회

I am trying to search for a certain letter in the last line of a text with always different numbers of lines. I have already managed the search for the letter, I am only missing the possibility to limit the search to the last line. Sometimes it is only one line and sometimes two or even more.

var t = sourceRectAtTime().top;
var h = sourceRectAtTime().height;
var y = t + h;

var txt = text.sourceText;
var find = txt.includes("p");

if(find == true){[value[0], y-5]} else {[value[0], y]}

 

I tried it with .split("r")[x]; but I can only select a certain line, which doesn't help if I don't know which one is the last.

var t = sourceRectAtTime().top;
var h = sourceRectAtTime().height;
var y = t + h;

var txt = text.sourceText;
var t1 = txt.split("r")[0];
var t2 = txt.split("r")[1];
var t3 = txt.split("r")[2];
var t4 = txt.split("r")[3];


var find = t2.includes("p");

if(find == true){[value[0], y-5]} else {[value[0], y]}

 

Thanks for helping me!

이 주제는 답변이 닫혔습니다.
최고의 답변: Dan Ebberts

Something like this maybe:

var t = sourceRectAtTime().top;
var h = sourceRectAtTime().height;
var y = t + h;

var txt = text.sourceText.split("\r");
y  -= txt[txt.length-1].indexOf("p") > -1 ? 5 : 0;
[value[0], y]

1 답변

Mylenium
Mylenium
Legend
July 13, 2023

The last line is simply the last entry in the array you create with .split():

 

mLast=txt.split("\r").length;

 

From there addressing the last line is simply mLast-1 to adjust for the different counting and that is the only line you need to test. Your syntax seems botched, though. a carriage return is \r, not just r.

 

Mylenium

M
Marketing310340444dbt작성자
Participant
July 13, 2023

Thank you very much for your answer. I'm not quite sure how to implement the line in my code, unfortunately. I don't have much experience with expressions yet. Can you give me an example?

Dan Ebberts
Community Expert
Dan EbbertsCommunity Expert답변
Community Expert
July 13, 2023

Something like this maybe:

var t = sourceRectAtTime().top;
var h = sourceRectAtTime().height;
var y = t + h;

var txt = text.sourceText.split("\r");
y  -= txt[txt.length-1].indexOf("p") > -1 ? 5 : 0;
[value[0], y]
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