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YesIAmDwight
Inspiring
September 2, 2020
Question

Decal/Material Size and Orientation Function

  • September 2, 2020
  • 3 replies
  • 2847 views

Maybe I'm missing it, but I can't find a tutorial on how to do this and the feature has been requested as far back as 2017 so I can't fathom why it wouldn't be blatantly obvious where to find it or how to do it by now so I'm hoping someone here can help me.

 

Let's my project settings are set to 300dpi and I have a flat object 8 inches wide and 10 inches long. I have a graphic perfectly sized at 300dpi that is also 8 inches wide and 10 inches long.

 

How do I cover the object with the image so that it is perfectly aligned and sized?

 

Where is the functionality to specify the size, position and rotation of an image/decal/material/whatever-fake-name-Aobe-arbitrarily-calls-this according to the object?

 

Thanks!

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3 replies

Known Participant
August 22, 2023

I'm voting for this.

getting control of size  of a decal is mandatory in many case.

using texture in a shader is fine in some case when applying an image of a square face, but when the texture must be applied on a group of adjacent faces it don't works any more unles you manage the unwrapping of your UV's what is impossible in Dimension, when Dimension generate UVs by itself

Ussnorway7605025
Brainiac
September 3, 2020

I'm saying the AI in V1&2 is less bloody minded when it comes to decals but the models | materials and rendor engine are also different so sometimes one V is just better at giving you the result you need than the other... I have V3 on my Ryzen [which eats complex rendors] and its a case of using the right tool which just comes from lots of testing mate

 

p.s, Adobe servers are having another bad day today so you may get an issue watching the example Vid I posted... if so, open the frame in its own Window to bypass this forum auto-buggering it up

YesIAmDwight
Inspiring
September 3, 2020

I think I understand.

 

So I guess my question is why are they insisting on doing it this way and leaving precise texturing to an AI when they could simply allow users to adjust dimensions down to the pixel like they do in every other Adobe program? It seems entirely alien to the Adobe brand. And they are well aware of this?

Colin Holgate
Inspiring
September 3, 2020

I didn't know anything about the AI stuff. I tried to reproduce my steps with your image, and then did get cropping. I tried quite a lot of things, then went back to my image, and I couldn't get it to be right either.

After all of the tests I did, I think I have concluded that there is an assumption that your image is square. You can get what you want by making a 10x10 plane, drag your 10x8 image on to the base color swatch, then tell the plane to have a Z size of 8 inches.

 

Colin Holgate
Inspiring
September 2, 2020

While the material is selected you can choose in the properties whether it is a decal or a fill. If it is a decal you can scale or rotate it, either directly with the controls on the object, or by using the values in the properties panel. If it is a fill you can set the number of times it repeats on X and Y. If those are both 1, it should exactly fill the area.

YesIAmDwight
Inspiring
September 2, 2020

You'd think that would be the case, but it either patently isn't or, again, there is something I am missing completely. Or maybe it's a bug?

 

Here are my project settings, you can see they are set to 300dpi

 

And here, you can see my decal image settings are also set to 300dpi with the dimensions as 8inches by 10inches

 

Here, you can see I created an object that is also 8inches by 10inches

 

However, if I apply the image as a decal, this is its scale and position.

 

At this point, I can see no option to tell Dimension to make the decale 8inches by 10inches or even specify in pixels. Also, the size is grossly incorrect. Even if I were to stretch it with proportions locked, the vertical edges will meet before the horizontal edges, indicating Dimension has squeezed the image for some inexplicable reason.

 

And if I set it as a fill with a repeat set to 1, this is the result.

Colin Holgate
Inspiring
September 2, 2020

Did you then try the offset values?