Exit
  • Global community
    • Language:
      • Deutsch
      • English
      • Español
      • Français
      • Português
  • 日本語コミュニティ
  • 한국 커뮤니티
1

Create a grayscale table chart in illustrator

Participant ,
May 31, 2020 May 31, 2020

I have 10x10 rectangles, I want to fill all selected items gradually from exact 0 to 1 lightness values.

I tried to write this one below but it doesn't really clamp for the blackest point. (RGB values still show as 3,3,3) What am I missing? And also there should be an easier solution for it.

grayscale_table_chart.jpg

 

// Fill all selected items with gradually from black to white
var doc = app.activeDocument;
var rgbCol = new RGBColor();
var col = [];

doc.defaultFillColor = rgbCol;
var hslColor = [];
var hue = hslColor.push(hue);
var saturation = hslColor.push(saturation);
var lightness = hslColor.push(lightness);
var selectedCount = app.selection.length;

function hslToRgb(h, s, l) {
  var r, g, b;
  if (s == 0) {
    r = g = b = l; // achromatic
  } else {
    function hue2rgb(p, q, t) {
      if (t < 0) t += 1;
      if (t > 1) t -= 1;
      if (t < 1/6) return p + (q - p) * 6 * t;
      if (t < 1/2) return q;
      if (t < 2/3) return p + (q - p) * (2/3 - t) * 6;
      return p;
    }
    var q = l < 0.5 ? l * (1 + s) : l + s - l * s;
    var p = 2 * l - q;
    r = hue2rgb(p, q, h + 1/3);
    g = hue2rgb(p, q, h);
    b = hue2rgb(p, q, h - 1/3);
  }

  return [ r * 255, g * 255, b * 255 ];
}

function clamp(num, min, max) {
  return num <= min ? min : num >= max ? max : num;
}

function main() {

     for (var a=0; a<selectedCount; a++)  
     {  

              hslColor[0] = 0;
              hslColor[1] = 0;
              value =  (100 - (a * (100/selectedCount)))/100;
              hslColor[2] = clamp(value,0.0,1.0);
              //alert (hslColor[2]);
              col = hslToRgb(hslColor[0],hslColor[1],hslColor[2]);
              rgbCol.red = col[0];
              rgbCol.green = col[1];
              rgbCol.blue = col[2];
              app.selection[a].filled = true;
              app.selection[a].fillColor =rgbCol;
     }  
}
main();

 

TOPICS
Scripting
1.1K
Translate
Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines

correct answers 1 Correct answer

Community Expert , May 31, 2020 May 31, 2020

Hi arteangelus,

 

Here is a simpler starting point:

 

var items = app.activeDocument.selection;
for (var j = 0; j < items.length; j++) {
    var k = (j / (items.length - 1)) * 100;
    items[j].fillColor = makeColorGray(k);
}

function makeColorGray(k) {
    var c = new GrayColor();
    c.gray = k;
    return c;
}

 

 

What do you think? Is it on the right track? If you wanted to keep the hue and saturation values but just change the lightness, perhaps you can use the k value calculation as lightness va

...
Translate
Adobe
Community Expert ,
May 31, 2020 May 31, 2020

Hi arteangelus,

 

Here is a simpler starting point:

 

var items = app.activeDocument.selection;
for (var j = 0; j < items.length; j++) {
    var k = (j / (items.length - 1)) * 100;
    items[j].fillColor = makeColorGray(k);
}

function makeColorGray(k) {
    var c = new GrayColor();
    c.gray = k;
    return c;
}

 

 

What do you think? Is it on the right track? If you wanted to keep the hue and saturation values but just change the lightness, perhaps you can use the k value calculation as lightness value in your own code?

 

Regards,

Mark

Translate
Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines
Participant ,
Jun 01, 2020 Jun 01, 2020
LATEST

Yes, definitely it also gives 0,0,0 as RGB in the beginning. Thank you.

Translate
Report
Community guidelines
Be kind and respectful, give credit to the original source of content, and search for duplicates before posting. Learn more
community guidelines