Looking Script to rotate objects

[j.khakase]

Hello Friends,

I am looking an illustrator script, which will rotate the selected objects. by its current rotate angle * 0

is this possible ?

[Disposition_Dev]

var selection = app.activeDocument.selection;

for(var s=0;s<selection.length;s++)

{

    selection[0].rotate(0);

}

[j.khakase]

Thank you for your reply. I test the code but it doesn't work in my case. I am attaching the screenshot the problem I am facing and the solution is expecting.

Please Refer the attached screenshot.

[Sergey Osokin · Accepted solution]

I have a script in the archive, unfortunately I do not know its author 🙂

doc = app.activeDocument;
sel = doc.selection;

first = 1;
ang = 0;
for (i = 0; i < sel.length; i++) {
  if (sel[i].typename == "GroupItem" || sel[i].typename == "PathItem" || sel[i].typename == "CompoundPathItem") {
    currGroup = sel[i];

    getFP = FindFirstPath(currGroup);
    currpath = getFP[1];

    if (getFP[0] == 1) {
      p1 = currpath.pathPoints[0].anchor;
      p2 = currpath.pathPoints[1].anchor;

      deltax = p1[0] - p2[0];
      deltay = p1[1] - p2[1];

      currang = Math.atan(deltay / deltax);
      if (deltax < 0)
        currang += Math.PI;

      if (first) {
        first = 0;

        ang = currang;
      } else {
        currGroup.rotate((ang - currang) * 180 / Math.PI);
      }
    }
  }
}

function FindFirstPath(workGroup) {
  if (workGroup.typename == "PathItem")
    return [1, workGroup];

  if (workGroup.typename == "CompoundPathItem")
    return [1, workGroup.pathItems[0]];

  nSubPathes = workGroup.pathItems.length;
  if (nSubPathes > 0)
    return [1, workGroup.pathItems[0]];

  nSubPathes = workGroup.compoundPathItems.length;
  if (nSubPathes > 0)
    return [1, workGroup.compoundPathItems[0].pathItems[0]];

  nSubGroups = workGroup.groupItems.length;
  if (nSubGroups == 0)
    return [0, 0];
  var currRet = [0, 0];
  for (iGroup = 0; iGroup < nSubGroups; iGroup++) {
    currRet = FindFirstPath(workGroup.groupItems[iGroup]);
    if (currRet[0] == 1)
      break;
  }
  return currRet;
}

[j.khakase]

Thank you so much Sergey Osokin, this works perfectly as I want. only one issue in this is we have to maintain the stacking order of layers. The reference group (here is the pink object) always should be at top before run the script. I never forget this is 2nd time you given me correct solution. Thanks lot 🙂

[j.khakase]

•And Reference object must be selected, while selecting others object to rotate

[CarlosCanto]

I have a script in the archive, unfortunately I do not know its author 🙂

By @Sergey Osokin

could it be from xpmycpc?

http://www.cnprint.org/bbs/showthread.php?t=259352

[Sergey Osokin]

Maybe. No other sources can be found. I will add this link to my local JS file.

[Met1]

Now that's cool, thanks.

[CarlosCanto]

but rotating by 0 or rotating by angle*0 would not apply any rotation, right?

[Disposition_Dev]

that is my understanding. doesn't matter what the current rotation is.. if you multiply it by zero, no rotation will occur. 

[femkeblanco]

I think they might have meant ° (degree symbol), as opposed to 0 (zero).

[CarlosCanto]

it makes sense, you might be 100% right

[Disposition_Dev]

I still don't think that would be enough information to provide any help. Unless they're asking for something to "rotate again" by just doubling the existing rotation angle? 

[j.khakase]

Thank you for reply. Please refer the shared screenshot

[Kurt Gold · Accepted solution]

Also see:

https://community.adobe.com/t5/illustrator-discussions/rotation/m-p/12443669

Apart from that, there is a very good script called Circular, provided by Alexander Ladygin. It has an option to reset rotations.

https://github.com/alexander-ladygin/illustrator-scripts

[j.khakase]

I am really very thankful to all, who replies on my query. and my problem is solved now 🙂