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Selections to Artboards ?

Forum|Forum|10 years ago
May 7, 2016
3 respuestas
3573 visualizaciones

Is there any script that can take a selection or multiple selections and make artboards from those selections and so the artboards fit perfectly to the selection ?

Scripting

Este tema ha sido cerrado para respuestas.

Mejor respuesta de CarlosCanto

try this

for (var a=0; a<selection.length; a++) app.activeDocument.artboards.add(selection.geometricBounds);

StrongBeaverAutor

Legend

My Layers panel is as such;

Layer1
-> Group
--> Letter1
--> Letter2
--> Letter3
--> Letter4
--> etc

The code I used was posted by Carlos in post #2, could it be the code won't work because the individual expanded letters are in a group ?

I completely oversaw post #6 by Carlos That is the result I want.

pixxxelschubser

Community Expert

StrongBeaver schrieb:
My Layers panel is as such;
Layer1
-> Group
--> Letter1
--> Letter2
--> Letter3
--> Letter4
--> etc
The code I used was posted by Carlos in post #2, could it be the code won't work because the individual expanded letters are in a group ?
I completely oversaw post #6 by Carlos That is the result I want.

pixxxel schubser schrieb:
Furthermore:
alert (app.activeDocument.selection.length);
alert (app.activeDocument.selection[0].typename);
…

It seems you completely oversaw my posting too:

pixxxel schubser schrieb:
… Because of:
If the selection is a group (if the word wasn't ungrouped after outlining) only one artboard will be added (with the code of CarlosCanto in his post #1)

Ungroup the group, select the letters and runs Carlos script again.

You will get:

the existing artboards remains
every part of selection.length will adds an new artboard (5 letters will adds 5 artboards, but a group with 5 letters will adds only one artboard !!! )

CarlosCanto

Community Expert

The point is, grouped or ungrouped, at least one artboard should be created, something should be happening

StrongBeaverAutor

Legend

I selected my selection, executed the code; but my selection was no placed on it's own artboard along side the artboard for which I selected my selection ?

CarlosCanto

Community Expert

please show screenshots of the results you're getting and the results you need.

pixxxelschubser

Community Expert

Actually my addition to the code does not seem to be working perfectly.

I think this is happening because the index order of the artboards is getting changed when artboards get deleted and then they get skipped. Not sure how to solve this yet…

Here is a before and after.

Before

After

Perhaps a bit more better

var idoc = app.activeDocument;
var abs = idoc.artboards;
for (var a=abs.length-1; a>=0; a--) {
    idoc.selection = null;
    thisBoard = abs;
    idoc.artboards.setActiveArtboardIndex (a); // activate each artboard
    idoc.selectObjectsOnActiveArtboard(); // select all in artboard
    if(!idoc.selection.length) {
        thisBoard.remove(); //Delete artboard if it is empty,
        } else {
        idoc.fitArtboardToSelectedArt(a); // fit artboard to selection
    }
}
idoc.selection = null;
idoc.rearrangeArtboards();

Have fun

CarlosCanto

Respuesta

Community Expert

try this

for (var a=0; a<selection.length; a++) app.activeDocument.artboards.add(selection.geometricBounds);

Disposition_Dev

Legend

This works great Carlos, as long as there are no clipping masks. Unfortunately, Illustrator treats the contents of the clipping mask as "visible" even though any artwork outside the clipping mask is not visible...

Hopefully you don't have clipping masks in your files, StrongBeaver.. If so, let us know and we'll try and help you out with that contingency.

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