How do we to get the corner points value from Quadrilateral?

[yajiviki]

Hi EveryOne!,

Is this possible to get the corner points value from Quadrilateral?

Thanks in advance.

-yajiv

[c.pfaffenbichler]

Nice of you to post a screenshot but please post a meaningful screenshot that includes the pertinent Panels. 

Are you talking about a Shape Layer for example? 

[yajiviki]

Hi c.pfaffenbichle,

Thank you for the prompt response.

Please find the meaningful screenshot below.

I need to get the cornerpoints value from the selection.

if I use activeDocument.selection.bounds code, It is show as 0,100 for topLeft.

However I need to get the value (100,145) instead of (0,100) viceversa for all sides.

Could yoy please share your suggestion.Inputs?

yajiv

[c.pfaffenbichler]

You misunderstood – the screenshot fails to illustrate if the blue shape is a Shape Layer or something else. 

[yajiviki]

Hi c.pfaffenbichle,

It is a pixel layer not a Shape Layer.

[c.pfaffenbichler]

And is it definitely always going to be a four sided shape?

So that there is always only going to be one extreme point in all four directions? 

Can there be cases where one or more sides may be perfectly vertical or horizontal? 

What is this about anyway? Is it a task that arises often enough that it’s worth automating? 

[c.pfaffenbichler]

I can’t remember who posted it but in a recent thread someone provided a neat solution by, if I remember correctly, evaluating the bounds and then intersecting row/column selections with the original selection an the four extremes. 

Those resulting four selections can then be evaluated to get the »missing« coordinate for all four extremes. 

How experienced are you with JavaScript and Photoshop’s DOM (and maybe AM)? 

[c.pfaffenbichler · Accepted solution]

Another approach would be creating a Working Path from a Selection based on the Layer’s transparency and evaluating that path. 

[yajiviki]

Hi c.pfaffenbichle,

Thank you for your detailed explanation.

I'm bit familiar with both DOM and AM code.

I'll try with work path method and let you know how it is working.

[c.pfaffenbichler]

Depending on the Selection and the Working Path settings the resulting Path may have a lot of »useless« points, so filtering out the corner points might be an interesting challenge. 

[yajiviki]

Hi c.pfaffenbichle,

Thank you for sharing the idea. My work path is very simple with 4 nodes.

I consider each point as a corner and your Idea working like charm.

Thank you so much.

- yajiv

[c.pfaffenbichler]

With a Shape Layer the issue could simply be addressed by getting the PathPoints’ coordinates. 

Other things (a pixel Layer of the object, the object just pixels on a larger Layer, …) would necessitate other approaches. 

[mushroom bomb]

Hello, could you please tell me if you have solved this problem with the script?

[c.pfaffenbichler]

What is your scenario? 

Could you please post screenshots with the pertinent Panels (Toolbar, Layers, Options Bar, Paths, …) visible? 

[mushroom bomb]

Thanks for your reply! As shown in the picture, I need to mark a logo on one of the corners of the two black spots (usually the left corner). I don’t know how to calculate the coordinates of finding this place now because I will have many different pixels. The pattern needs to be like this

[c.pfaffenbichler]

I don’t understand, is this the object you need to identify the corners of or a »target« object onto which the logo will be placed/transformed/…? 

The curvature of the sides would make identifying the corners via a Photoshop Script difficult, possibly impossible. 

[mushroom bomb]

I only need the coordinates of this place, because I can solve it by adding other materials after getting the coordinates. Thank you very much again for your reply. This problem bothers me very much. I think about it even in my sleep and dreams. I even started to try to draw a circle on this shape according to the size of this shape. After aligning the shape, I used the edge of this circle to calculate the distance. Far away (that is, this black dot)

[c.pfaffenbichler]

The shape’s borders appear very crisp – is it (or was it previously) a vector shape/object? 

That might make determining specific point easier. 

[mushroom bomb]

Yes, it's a hard pixel image of a vector

[c.pfaffenbichler]

Yes, it's a hard pixel image of a vector

By @mushroom bomb

Did you rasterize a pdf/eps/ai/svg/… or does the Path exist in the Photoshop file? 
Can you provide the vector data? 

[mushroom bomb]

No, I just have a simple pixel image. If necessary, I can turn this layer into a path in advance and display it in the path list flash.

[c.pfaffenbichler]

Do you need to work with many such files? 

Please provide a sample file. 

[mushroom bomb]

Just like the groups in this file, I will have many such pictures for a long time. I need to locate the black spots and add a letter. The shape of the layer will be different each time, and there will be multiple groups in one document. need this

[mushroom bomb]

[r-bin]

I think about it even in my sleep and dreams.

By @mushroom bomb

Just a demo.

Before running, you need to create a selection from shape.

This script finds and selects the lower left corner of the shape as one pixel.

It also puts guides on it.

Tested on CS6 on the provided tiff file. I have no way to test on CC.

var doc = activeDocument;
var tmp = "tmp"+Math.random();

var ok = true;

try { doc.selection.bounds; } catch (e) { alert("No selection"); ok = false; }

if (ok)
    {
    activeDocument.suspendHistory("script", "main()");
    }

///////////////////////////////////////////////////////////////////////////////////////////////////
function main()
    {
    try {
        app.preferences.rulerUnits = Units.PIXELS;

        var w = doc.width.value;
        var h = doc.height.value;

        save_selection(tmp);

        var from = scan(0, w/2, h, 50);

        scan(from, from+50, h, 1);

        del_channel(tmp);

        doc.guides.add(Direction.VERTICAL, doc.selection.bounds[0])
        doc.guides.add(Direction.HORIZONTAL, doc.selection.bounds[1])
        }
    catch(e) { alert(e.line+"\n"+e); }
    }

///////////////////////////////////////////////////////////////////////////////////////////////////
function scan(from, to, max, step)
    {
    try {
        app.preferences.rulerUnits = Units.PIXELS;

        for (var i = from; i <= to; i+=step)
            {
            load_selection(tmp);

            doc.selection.select([[0,max-i], [0,max-i-1], [i+1,max], [i,max]], SelectionType.INTERSECT, 0, false);

            try { doc.selection.bounds; } catch (e) { continue; }

            break;
            }

        return i-step;
        }
    catch(e) { alert(e.line+"\n"+e); }
    }

///////////////////////////////////////////////////////////////////////////////////////////////////
function save_selection(name)
    {
    try {
        var d = new ActionDescriptor();
        var r = new ActionReference();
        r.putProperty(stringIDToTypeID("channel"), stringIDToTypeID("selection"));
        d.putReference(stringIDToTypeID("null"), r);
        d.putString(stringIDToTypeID("name"), name);

        executeAction(stringIDToTypeID("duplicate"), d, DialogModes.NO);
        }
    catch(e) { alert(e.line+"\n"+e); }
    }

///////////////////////////////////////////////////////////////////////////////////////////////////
function load_selection(name)
    {
    try {
        var d = new ActionDescriptor();
        var r = new ActionReference();
        r.putProperty(stringIDToTypeID("channel"), stringIDToTypeID("selection"));
        d.putReference(stringIDToTypeID("null"), r);
        var r1 = new ActionReference();
        r1.putName(stringIDToTypeID("channel"), name);
        d.putReference(stringIDToTypeID("to"), r1);
        executeAction(stringIDToTypeID("set"), d, DialogModes.NO);
        }
    catch(e) { alert(e.line+"\n"+e); }
    }

///////////////////////////////////////////////////////////////////////////////////////////////////
function del_channel(name)
    {
    try {
        var d = new ActionDescriptor();
        var r = new ActionReference();
        r.putName(stringIDToTypeID("channel"), name);
        d.putReference(stringIDToTypeID("null"), r);
        executeAction(stringIDToTypeID("delete"), d, DialogModes.NO);
        }
    catch(e) { alert(e.line+"\n"+e); }
    }