Script to delete the last (recent) Layer Comps? (specify amount to a func)

Brainiac

It is probably easier to create temporary LayerComps with a fixed or standard name, for example, TMP or TMP1, TMP2, etc., perhaps using a script (or action), and then delete these temporary LayerComps based on the name.

Known Participant

I have this idea often but never tried it.

I would wanna keep meaningful names though, so I'm usually wondering if I can delete layers based on a prepended code.

For example, ...

tmp_ Meaningful description 1

tmp_ Meaningful description 2

tmp_ Meaningful description 3

Then delete all Comps starting with tmp_

Known Participant

while((lCs = (aD = activeDocument).layerComps).length &&
(lC = lCs[lCs.length - 1]).name.split(/^TMP_/)[1]) lC.remove()

(1) Your code did exactly what I needed at the time: it deletes Layer Comps prepended with "– ", but only from the bottom up.

As it doesn't work to remove any prepended LC, I've been trying to rewrite it using a "for" loop structure, but I'm ashamed to always get errors...

(Help 😛 )

I want removed: – LC 3, – LC 6, – LC 4

UPDATE.: Figured it out, I think...

var doc = app.activeDocument;

   for(i = doc.layerComps.length-1; i >= 0 ; i--){
        if( doc.layerComps[i].name.split(/^– /)[1] ){
            doc.layerComps[i].remove();
        }
    }

(2) Also, to execute "next Layer Comp," it works using Script Listener code or xtools "action to script," but is that the fastest way? (This doesn't have to fly of course; just wondering if there is shorter code that is not 50ms slower.)

Brainiac

app.activeDocument.layerComps.removeAll();

Do you need this?

Known Participant

I probably got that out of a PDF... 😉

That's what I've been using.

But it doesn't respect what was already there. That's what I now wanna improve on.

Known Participant

Visual example ...

An action makes 3 layers: R, G, B

I use the Layer Comps the action also made to flip through them and see what I prefer.

I decide to keep Green. My action removes Red and Blue layer.

I now want the R, G, B Comps gone (3 last ones). They were just for flipping through the variations.

Known Participant

In this simple example, I can let the action do the cleanup of the Comps too. But it's messier and more work than calling a script to "Delete last 3 Comps." It feels safer to me too (while it may not be...).

Brainiac

If you had read Photoshop JavaScript Ref.pdf at least once, there would have been no questions.

Known Participant

That's possible, but then forums should not exist maybe.

That is some pretty "boring stuff" and I always end up having to search the net to see an example I understand..

I do always consult the two 2 pdfs but I'm not familiar with methods by just seeing keywords...

The pdfs hardly have an example in them.

I just need small bits usually, but less obvious ones on many occasions.

More to follow... 😉

I am someone that hates asking and have usually spent half the day (or even years) on it already... 😉

I'm now just asking a bunch in a row, so I am done.

Well, I guess it never stops.... 😜

Kukurykus

Brainiac

I agree, Adobe docs is unfriendly for beginners, especially those with no coding experience.

Brainiac

Who said the last one on the list is the most recent? 🙂

Known Participant

I don't know if it is so on the inside...

I am just assuming since I'm removing them very soon after I created them... (and visually they always seem to add on to the bottom).

Kukurykus

Brainiac

while((lCs = activeDocument.layerComps).length > 2) lCs[lCs.length - 1].remove()

Known Participant

You replied before I asked! 😉

I'm waiting for r-bin's faster version now... 😉

Seriously... Thanks again!

But I can't figure out how to do it in one line, if possible?

Why does this give an error if I wanna remove the last 3?

while( (lCs = activeDocument.layerComps).length > 0) lCs[lCs.length - 3].remove()

Known Participant

Ok, I think I get why it fails..

Just have to put that line in another loop then or something...