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pixxxelschubser

Community Expert

pixxxel schubser

active since 2009 | 6100+ posts

pixxxelschubser

Community Expert

pixxxel schubser

active since 2009 | 6100+ posts

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Hello, I prefer the slice-method. Take a look at this example: // at first - open a document, then run script var aDoc = app.activeDocument; var aName = aDoc.layers[0].name; alert(aName); var newName = "LayerXYZ"; // Changing the new name of top level aDoc.layers[0].name = newName; // display the new name | the result will be: LayerXYZ alert ("The new name of this Layer is: " +newName); // shorter Variable newName = aDoc.layers[0].name.slice(0,-3); // Changing the new name of Layer 1 aDoc.layers[0].name = newName; // display the new name | the result will be: Layer alert("The new short name of this Layer is: " +newName);

Please, show it to us

Hi CarlosCanto, this is funny. The same answer I gave to the thread opener at noon today in another forum: http://www.hilfdirselbst.ch/foren/Print_Probleme_im_Illustrator_-_Scripte_P506095.html?sb=post_latest_reply;so=ASC;forum_view=forum_view_collapsed;;page=unread#unread

Loop through subfolders e.g. like this: http://forums.adobe.com/message/3139217#3139217

That would be the easiest option: #target Illustrator // Remove9of10.jsx // graph must be breaked; // only if category axis is the x-axis; // all selected tick marks must be ungrouped; // http://forums.adobe.com/thread/1095789?tstart=0 // the first tick mark (normaly on position 0 in graph) is also deselected/removed // by pixxxelschubser var myDoc = app.activeDocument; var Sel = myDoc.selection; var SelLen = Sel.length; var p1 = Sel[0].position[0]; var p2 = Sel[SelLen-1].position[0]; var x = 10; x = prompt ("Receive each xth line", x); if (p1 != p2) { if (p1 < p2) { for ( i = SelLen-1; i >= 0; i--) { if (i/x != Math.round (i/x) || i/x == 0) { Sel.selected = false; //to remove, change this line with next line //Sel.remove(); redraw(); } } } else { for ( i = 0; i <= SelLen-1; i++) { if (i/x != Math.round (i/x) || i/x == 0) { var j= SelLen-1 - i; Sel .selected = false; //to remove, change this line with next line //Sel .remove(); redraw(); } } } } else { alert("only for x-axis") } Have fun

I already suspected. Thanks for your attempt.

I'll try it tomorrow again. At home I only have CS3.

CS6 is brand new in our company since yesterday. I hope so much that I'm going to find a solution. Because usually I always use a placeholder text in edittext-box in most scripts. Bad news for me ... Probably textselection property is not really the tool of choice for me.

In earlier versions of Illustrator, the text of an edittext-box in a dialog box was automatically selected and highlighted by edittext.active = true; Now in CS6 is only the cursor in text box - no highlighting more. How can I restore the "original state" (javascript in Illustrator CS6, Mac OS and Windows)?

Try this on a single textFrame with numbers and following Letter: #target Illustrator // RoundNumBeforeLetter.jsx // http://forums.adobe.com/thread/1095744?tstart=0 // rundet Zahlen vor einem Buchstaben var myDoc = app.activeDocument; var myTxt = myDoc.textFrames[0]; //the first TextFrame in document var myTxtCharLen = myTxt.characters.length; var myTxtNum, j, LastChar = null; for (i=0; i <=myTxtCharLen-1;i++) { myTxtChar = myTxt.characters.contents; if (SearchText(myTxtChar) == true) { j = i; myTxtNum = myTxt.contents.slice (0,j); myTxtNum = Math.round (myTxtNum); LastChar = myTxt.contents.slice (j); myTxt.contents = myTxtNum+LastChar; } } function SearchText(x) { var myRegExp = /(^-?[A-Z]$)/; return myRegExp.test(x); } Maybe it's not as elegant. On the contrary, it probably is "complicated and a long way around," but should work.

Thanks for the great tuition. CarlosCanto wrote: … phew!! that was hard, grammar proved to be more difficult than programming!! hahaha Now you know how I feel. I learned „my English“ 25 years ago and since then no longer needed. Scripting is indeed easier.

Yes, I agree completely with you. That was exactly, what I would like saying before. (Or: That was exactly what I want to say before.) ??? Do you know, what I mean?

It's difficult to "break" graph with script, because you get grouped grouped grouped items. IMHO the problem will be to select the tick marks with script. To deselect or remove 9 of 10 (or of 100) lines you can give this script a chance: #target Illustrator // Remove9of10.jsx // graph must be breaked; // only if category axis is the x-axis; // all selected tick marks must be ungrouped; //the first tick mark (on position 0 in graph) is also deselected/removed //by pixxxelschubser var myDoc = app.activeDocument; var Sel = myDoc.selection; var SelLen = Sel.length; var p1 = Sel[0].position[0]; var p2 = Sel[SelLen-1].position[0]; if (p1 != p2) { if (p1 < p2) { for ( i = SelLen-1; i >= 0; i--) { if (i/10 != Math.round (i/10) || i/10 == 0) { Sel.selected = false; //to remove, change this line with next line //Sel.remove(); redraw(); } } } else { for ( i = 0; i <= SelLen-1; i++) { if (i/10 != Math.round (i/10) || i/10 == 0) { var j= SelLen-1 - i; Sel .selected = false; //to remove, change this line with next line //Sel .remove(); redraw(); } } } } else { alert("only for x-axis") }

Thanx for your example-file. But what I really need is a file with numbers before and after using script. (Please CS3-conform)

Please show some examples of your numbers and a screenshot with visible layers palette..

@Harsh V Sharma, please read my last post again - carefully. @CarlosCanto

Sorry, but your code is terrible posted in forum. …(like my English) I think the counter i is not used in win.pnl And because the steps are defined anyway : win.pnl.progBar.value + = 10; try this: while(win.pnl.progBar.value<100) instead of: for(i=0; i<10; i++)

Are the lines in text frames or text areas? and I repeat: CarlosCanto wrote: … what else do you need to do with the 10 selected lines, or with the 90 other deselected lines?

What's the content of your textFrames? Rounding: up or down or mathematical or other? e.g. like this: var x = 123.4567; alert (Math.round (x*10)/10); alert (Math.round (x)); Try it.

@Harsh V Sharma, you have now found a solution? Or you can answer my previous posting?

additional to previous ingenious post of [Jongware]: // for a single TabStop with decimal alignment var myDoc = app.activeDocument; var myDocName = myDoc.name; var t = new Array(); t[0] = new TabStopInfo; with (t[0]) { position = 120; // in pt decimalCharacter = "."; // standard alignment = TabStopAlignment.Decimal; } var aText = myDoc.textFrames.add(); with (aText) { contents = myDocName + "\t120.00 Decimalpoint-TabStop"; left = 0; top = 0; paragraphs[0].tabStops = t; }

@Harsh V Sharma, please show your code for the progress bar completely. ( I can't find win.update() in your code). Also this call is only needed, if you work under MacOS. The palette works fine under Windows OS without win.update().

Hello CarlosCanto, as a supplement for your post #8. It is possible to search for some spaces of special kind – search for the Unicode of the characters e.g. like this: open a new document and zoom out, then start the script (when the script is running, observe the new textframe; CS3 at left bottom, CS5 at left top of artboard) // FindSearchReplaceSomeSpecialSpaces.jsx var aText = app.activeDocument.textFrames.add(); with (aText) { contents = "Thinspace \u2013\u2013\u003e\u2009\u003c\u2013\u2013 Hairspace \u2013\u2013\u003e\u200A\u003c\u2013\u2013" } redraw(); alert(aText.contents); aTCon = aText.contents; aText.contents = replaceSpecialSpace(aTCon); alert("Achtelgeviert ersetzt durch \u0040\r1/24-Geviert ersetzt durch \u00a9") function replaceSpecialSpace() { aTCon = aTCon.replace( /\u2009/g, '\u0040' ); // Achtelgeviert --> @ aTCon = aTCon.replace( /\u200A/g, '\u00a9' ); // 1/24-Geviert --> © aTCon = aTCon.replace( /[A-Z]+/gi, "replaced:" ); return aTCon; } Have fun

What happens when you run the script from Illustrator out?

Please try this: var Folder2Open = new Folder("~/Desktop/nik.1"); if(Folder2Open.exists) { var myFolder = Folder2Open.selectDlg("Choose PDF output folder:"); } else { alert ("Folder doesn't exist") }

Hello Muppet Mark, I have completed my script before half a week. That's why your link was unfortunately a few days too late for me. Nevertheless seems linked script to the behance.net page to allow a much more comfortable reading and passing the path point locations in a *. jsx file. Maybe I sign on the page and test the script. Greetings pixxxelschubser

A little update. @ Muppet mark, your two answers were helpful, but now I am afraid to try another way. The main script needs to run on several computers, so it is not good to distribute many more files. I have written to me for each file a function that draws the paths. This is probably the best way for me. I thank you again for your answers. regards

Hallo martin_Cahill, My English is not the best, because of that in German. Grundsätzlich sind sich VBA und Javascript sehr ähnlich. Versuche die folgende Funktion mit den VBA-Äquivalenten zu vergleichen. Learning by doing function makeRect() { if (selection.length == 0) { alert("Kein Objekt …"); return; }else{ if (selection.length > 1) { alert("Zu viele Objekte …"); return; }else{ var myDoc = app.activeDocument; var Sel = myDoc.selection var SelVB = Sel[0].visibleBounds; var dMarg = 28.3464567; var Links = SelVB[0]; var Oben = SelVB[1]; var SelBreite = (SelVB[2] - SelVB[0]); var SelHoehe = (SelVB[1] - SelVB[3]); var newCMYK = new CMYKColor(); newCMYK.cyan = 100; newCMYK.magenta = 0; newCMYK.yellow = 0; newCMYK.black = 0; var myGroup =myDoc.groupItems.add(); Sel[0].move(myGroup, ElementPlacement.PLACEATBEGINNING); var MargBox = myDoc.pathItems.rectangle(Oben+dMarg, Links-dMarg, SelBreite+2*dMarg, SelHoehe+2*dMarg); MargBox.stroked = true; MargBox.strokeWidth = 10; //MargBox.filled = false; MargBox.fillColor = newCMYK; MargBox.move(myGroup, ElementPlacement.PLACEATEND); } } } Hilft dir das weiter? Viel Spass noch.

Sind mehrere Objekte ausgewählt, dann z.B. so (das Ergebnis wird in Millimeter ausgegeben): var Sel = app.selection.length for (i = 0; i < Sel; i++) { alert("X0 von Objekt " + i + " = " +app.activeDocument.selection.position[0]*0.3527778 + " mm","Links"); alert("Y1 von Objekt " + i + " = " +app.activeDocument.selection.position[1]*0.3527778 + " mm","Oben"); } Viel Spass

Okay, createsFromFile() gives the same grouped grouped groupItem with also two clipping paths. Nevertheless, this seems to be the more direct route. Thank you. Probably I need in any case to loop through items to delete the clipping Paths? Is that so?