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Irina5F96
Participant
Feb 8, 2021 6:06 PM UTC
Answered

loopOut is not a function

When I use expression loopOut() I always see error "loopOut() is not a function". I tried to use different variants of syntaxes but it didn't help.

I saw some advices here but they didn't work too.

 

I use Mac OS Big Sur 11 and 17.6.0 After Effects

    Cidietrich_
    Cidietrich_Correct answer
    Participant
    Mar 12, 2024 1:43 PM UTC

    I Had the same problem today and I realised you have to use de entire expression not just "LoopOut("offset")" like some tutorials tells us to do. You Have to use like this:

    loopOutDuration(type = "offset", duration = 0)

     

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    9 replies

    Cidietrich_
    Cidietrich_Correct answer
    Participant
    Mar 12, 2024 1:43 PM UTC

    I Had the same problem today and I realised you have to use de entire expression not just "LoopOut("offset")" like some tutorials tells us to do. You Have to use like this:

    loopOutDuration(type = "offset", duration = 0)

     

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      Blake612
      Participating Frequently
      Aug 1, 2021 6:41 PM UTC

      Any chance there's a way to trick things into working like loopOut("pingpong")? 🙂

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        Dan Ebberts
        Community Expert
        Dan EbbertsCommunity Expert
        Community Expert
        Aug 1, 2021 6:54 PM UTC

        That would be like this:

        if (numKeys > 1 && time > key(numKeys).time){
  t1 = key(1).time;
  t2 = key(numKeys).time;
  span = t2 - t1;
  delta = time - t2;
  seg = Math.floor(delta/span);
  t = delta%span;
  valueAtTime((seg%2) ? (t1 + t) : (t2 - t));
}else
  value
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          Airu24321326m5x9
          Participant
          Sep 28, 2022 3:05 AM UTC

          Hi,

          I am wondering how do I target this only on specific keyframe(s), like how the in and out under loop function and numKeyframes are doing? Thanks!

          Really apprciate your contribution of that code

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          Community Expert
          Rick GerardCommunity Expert
          Community Expert
          Feb 8, 2021 6:52 PM UTC

          The loopOut() function works on properties that have a numeric value. The values can be in an array. Vector paths require a different approach.

           

          The approach is to look at the number of keyframes and then use valueAtTime(). 

           

          For a simple seamless loop, the first and last keyframes must be identical so copy the first keyframe and paste it at the end. This is the simplest approach to that problem:

           

          valueAtTime(time % key(numKeys).time)

          Edit: Just saw Dan's solution. It's a lot more typing and it has the advantage of not throwing an error if there is only one keyframe.

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            Dan Ebberts
            Community Expert
            Dan EbbertsCommunity Expert
            Community Expert
            Feb 8, 2021 6:32 PM UTC

            loopOut() doesn't work for paths. Try this workaround:

            if (numKeys > 1 && time > key(numKeys).time){
  t1 = key(1).time;
  t2 = key(numKeys).time;
  span = t2 - t1;
  delta = time - t2;
  t = delta%span;
  valueAtTime(t1 + t);
}else
  value
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              Anonymous
              Jul 28, 2021 2:26 PM UTC

              It works flawlessly 😄

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