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B
Blue-Marble
Known Participant
February 11, 2024
Answered

Can't use thisComp in a path on parented text. How can I overcome this?

  • February 11, 2024
  • 2 replies
  • 872 views

I want to rotate three words around a null object. Easy. Parent the words to the null and hit one rotation property. Then, apply this "value - parent.transform.rotation" on each word's rotation to keep them upright.

 

I then wanted to make it look better by having lines between the words. The points of each line are references using thisComp to point to the words as shown below:

 

p1 = thisComp.layer("Word1").position;
p2 = thisComp.layer("Word2").position;
pts = [p1, p2];
createPath(pts, inTangents = [], outTangents = [], isClosed = false)

 

This does not work because the expression can't use thisComp to connect the lines. This is because the line points then go to 0,0, which is what the anchoring values become when parented to the null. Now I need a better configuration or expressions to make it work with just a null, three words and three lines. I am trying to create a fluid triangle shape based on the layer's position but only needing one rotation property to the keyframe instead of keyframing each word's positions and making non-uniform triangles.

 

 

 

    This topic has been closed for replies.
    Correct answer Dan Ebberts

    You're probably looking for something like this:

    L1 =thisComp.layer("Simplifi");
L2 = thisComp.layer("RFiD");
p1 = fromComp(L1.toComp(L1.anchorPoint));
p2 = fromComp(L2.toComp(L2.anchorPoint));
p =[p1,p2];
createPath(p,[],[],false)

    2 replies

    A
    Airweb_AE
    Legend
    February 11, 2024

    You can parent the Shape Layer to the Null and set the position to [0,0]

     

    Text Layers Position:

    radius = 400;
x = Math.cos(degreesToRadians(120) * (index - 1)) * radius;
y = Math.sin(degreesToRadians(120) * (index - 1)) * radius;
[x,y]

     

    Text Layers Rotation:

    value - parent.rotation

     

    Shape Layer Path:

    p1 = thisComp.layer("Word 1").position;
p2 = thisComp.layer("Word 2").position;
p3 = thisComp.layer("Word 3").position;
pts = [p1, p2, p3];
createPath(pts, inTangents = [], outTangents = [], isClosed = true)

     

     

    B
    Blue-MarbleAuthor
    Known Participant
    February 12, 2024

    Thank you, this looks interesting. I definitely need to use a lot more math equations like this. It seems to have a lot more functionality than boring entry-level basics.

    Mylenium
    Mylenium
    Legend
    February 11, 2024

    Convert the coordinates using toWorld() or whatever other layer space transform method is appropriate.

     

    Mylenium

    B
    Blue-MarbleAuthor
    Known Participant
    February 11, 2024

    Could you please explain how this would work with an example? I need to learn this. I wouldn't know what layers space transform method is appropriate.  It's very much in a minimalist phase

     

    Dan Ebberts
    Community Expert
    Dan EbbertsCommunity ExpertCorrect answer
    Community Expert
    February 11, 2024

    You're probably looking for something like this:

    L1 =thisComp.layer("Simplifi");
L2 = thisComp.layer("RFiD");
p1 = fromComp(L1.toComp(L1.anchorPoint));
p2 = fromComp(L2.toComp(L2.anchorPoint));
p =[p1,p2];
createPath(p,[],[],false)
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