Create an array of arrays from a .txt file!

Hi,

Here my “obscure” version with error-handling and a final pop-up listing which layer was renamed.

I hope I'll be able to write as fine scripts as you do Peter,

Swo

//DESCRIPTION:Rename layers from text file
/*
Text file should contains 2 columns (old name;new name), line by line
separator is ";", can be changed at line 27
If script is unable to find layer_names.txt, it asks for a file.
No check for forbidden characters in names:
you need to check the text file before running the script.
*/
(function () {
    if (app.locale.toString() == "FRENCH_LOCALE") {
        var infos = {
            findFile:"Choisir le fichier contenant la liste de noms :",
            msg:" calque(s) renommé(s) :"
        };
    } else {
        var infos = {
            findFile:"Select the text file for layer names:",
            msg:" layer(s) renamed:"
        };
    }
    // Modify text file's name and separator (sepa) if needed
    var txtList = "layer_names.txt",
        sepa= ";";
   
    var oNames = [], nNames = [], rNames = [];
    var myListFile = File(myFindFile(txtList));
    // datas
    var testNames = listNames();
    if (testNames && oNames.length == nNames.length) {
        var myLayers = app.activeDocument.layers, c = 0;
       
        for (var L = 0; L < myLayers.length; L++) {
            var testN = false;
            for (var n = 0; n < oNames.length && !testN; n++) {
                if (myLayers.name == oNames && !app.activeDocument.layers.itemByName(nNames).isValid) {
                    myLayers.name = nNames;
                    // list renamed layers
                    rNames.push(oNames + " => " + nNames);
                    // ensure old name doesn't conflict with same new name :
                    oNames = "";
                    testN = true;
                    c++;
                }
            } // for n
        } // for L
        alert(c + infos.msg + "\n" + rNames.join("\n"));
    }
    function listNames() {
        // Open the file for reading
        myListFile.open("r");
        var text = myListFile.read();
        var lines = text.split("\n");
        if (lines.length > 0) {
            for (var y =0; y < lines.length; y++) {
                var l = lines;
                if (l.length != 0) {
                    if (l[0] !== "") {
                        var names = l.split(sepa);
                        if (names.length == 2) {
                            oNames.push(names[0]);
                            nNames.push(names[1]);
                        }
                    }
                } // l.length
            } // for
            return true;
        } // lines.length
        return false;
    }
    //////// FUNCTIONS ////////////
    function myFindFile(myFilePath) {
        var myScriptFile = myGetScriptPath();
        var myScriptFile = File(myScriptFile);
        var myScriptFolder = myScriptFile.path;
        myFilePath = myScriptFolder + "/" + myFilePath;
        if(File(myFilePath).exists == false) {
            //Display a dialog.
            myFilePath = File.openDialog(infos.findFile);
        }
        // else alert("ok");
        return myFilePath;
    }
    function myGetScriptPath() {
        try {
            myFile = app.activeScript;
        }
        catch(myError){
            myFile = myError.fileName;
        }
        return myFile;
    }
}());

Hi Obi-wan,

one split() and one loop with another split() can get you there.

Depending on the line separator—\n or \r—that could be:

var array1 = string.split("\r");
var array2 = [];
for(var n=0;n<array1.length;n++)
{
    array2[array2.length++] = array1.split(";")
};

Regards,
Uwe