ExtendScript, InDesign 2022: Return `parentPage`s of last cells of all tables

Seems like the problem with getting the character after the table is the table could have space after applied, which might force the character to the next page:

Hi Rob,

thank you for this! It's working very well with my test documents.

Your algorithm is superior* to the one where one is looking at the parent page of an insertion point in a table cell of the last body row. If Tobias does not mind I will mark your answer as the correct one.

Thanks,
Uwe Laubender
( Adobe Community Professional )

* EDIT: I have to add a comment and correct myself on this.

Rob's algorithm detects the right page if:

[1] There is no text after the table in the story

[2] If at least one character is rendered in the same text frame with the last row of the table.

But if the first character that comes after the table is rendered in a different text frame on a different page one can see that the position of the insertion point moved along with the character and the wrong page is detected as the last one of the table.

See Rob's reply her in the same discussion:

https://community.adobe.com/t5/indesign-discussions/extendscript-indesign-2022-return-parentpage-s-of-last-cells-of-all-tables/m-p/12947635#M477494

Uwe, this is pretty nasty, puh – thank you very much for pointing this out!

So for completeness sake:

$.writeln( findPagesOfLastCells() );

function findPagesOfLastCells() {
// https://community.adobe.com/t5/indesign-discussions/javascript-property-to-tell-if-text-is-in-a-continued-table/td-p/6379093
    var aDoc = app.activeDocument,
        allTables = aDoc.stories.everyItem().tables,
        thePages = []; 
    if( allTables.length > 0 ) {
        for ( var i = 0; i < allTables.length; i++ ) {
            var theTable = allTables[i];
            if ( theTable.rows.length > 1 ) {
                var lastRowPage = 0;
                var lastRowPage = getAOsParentPage( theTable.rows[-1-theTable.footerRowCount].cells[-1].insertionPoints[-1] );
                thePages.push(lastRowPage.name);
            }
        }
    }
    return thePages;
}

function getAOsParentPage(theAOReference) {
    var aDoc = app.activeDocument;
    var theAO = aDoc.rectangles.add({ geometricBounds: [0,0,5,5] });
    theAO.anchoredObjectSettings.insertAnchoredObject( theAOReference, AnchorPosition.ANCHORED );
    theAO.anchoredObjectSettings.releaseAnchoredObject();
    var theAOparentPage = theAO.parentPage;
    theAO.remove();
    return theAOparentPage;
}

But please be aware what Uwe pointed out in his first post of all further issues, which may be important for reusing this code in your own context!

My code wasn’t meant to be bullet-proof, but to show, that parentTextFrame doesn’t work in tables and to ask for help on this topic. And my second code showed an approach to deal with that limitation as a workaround.

I’m absolutely with you: To be bullet-proof there have to be much more fine grinding. Thanks for your annotations showing manyfold directions, which has to be taken into account.

But let me ask one question:

> I think it will make a big difference when allTables is an array and not a collection of tables:

Why is using array over object better? Are there any other reasons except performance?

Thanks,

Tobias

Thanks, @brian_p_dts for your kind answer. Meanwhile I’ve done some nasty bit of code. It works, but – puh! – it’s very hacky and ugly (because intrusive):

$.writeln( findPagesOfLastCells() );

function findPagesOfLastCells() {
// https://community.adobe.com/t5/indesign-discussions/javascript-property-to-tell-if-text-is-in-a-continued-table/td-p/6379093
    var aDoc = app.activeDocument,
        allTables = aDoc.stories.everyItem().tables,
        thePages = []; 
    if( allTables.length > 0 ) {
        for ( var i = 0; i < allTables.length; i++ ) {
            var theTable = allTables[i];
$.writeln('***********tables************\n'+theTable);
            if ( theTable.rows.length > 1 ) {
                var lastRowPage = 0;
                var lastRowPage = getAOsParentPage( theTable.rows[-1].cells[-1].insertionPoints[-1] );
$.writeln(lastRowPage);
                thePages.push(lastRowPage.name);
$.writeln(lastRowPage.name);
            }
        }
    }
    return thePages;
}

function getAOsParentPage(theAOReference) {
    var aDoc = app.activeDocument;
    var theAO = aDoc.rectangles.add({ geometricBounds: [0,0,5,5] });
    theAO.anchoredObjectSettings.insertAnchoredObject( theAOReference, AnchorPosition.ANCHORED );
    theAO.anchoredObjectSettings.releaseAnchoredObject();
    var theAOparentPage = theAO.parentPage;
    theAO.remove();
    return theAOparentPage;
}

If someone has a better idea, it’ll be very welcome ...

Thanks, Tobias