How to get full path of parent script that uses #include

Question

Script A has an #include "ScriptB" line.

ScriptB now needs the full path of Script A -- i.e., exactly the info you get from $.fileName if you run that line in Script A.

But the command $.fileName if it appears in Script B returns the path to Script B, not Script A. (I always thought that #include actually causes the contents of the #include statement to be copied over to that location, but this proves that it is not quite so simple.)

Obviously, this path could be assigned to a variable in Script A and then used in Script B. But Script B is a library component, and the whole point is not to have to update the two-dozen Script A's that are calling Script B. So I would rather not have to modify all the Script A's. It would be better if Script B stays an independent module.

So: How to get the full path of Script A, when you're inside Script B, which has been #included in Script A?

For a moment I thought I had found an answer: The first line of the string $.stack is the file name of Script A. But it doesn't include the path, just the file name, so not good enough.

Can anyone help?

Thanks,

Ariel

Loic.Aigon · Answer

Hi Ariel,What about ScriptArgs ?#include "scriptB.jsx"app.scriptArgs.set("origin", $.fileName );test();And in scriptB :function test() { var origin = app.scriptArgs.isDefined ( "origin" )? app.scriptArgs.get ( "origin" ) : "unknown"; alert( "Calling script location is :\r"+origin );}HTHLoic

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