Can you create circle with CreatePath expression?

[avpromedia]

Can you create a circle with CreatePath()?

If not, is there another way to create a circle using expression?

[Dan Ebberts]

Something like this should work:

r = 100; // radius
ratio = .5523;
t = r*ratio;
vertices = [[r,0],[0,r],[r,2*r],[2*r,r]];
inTangents = [[t,0],[0,-t],[-t,0],[0,t]];
outTangents = [[-t,0],[0,t],[t,0],[0,-t]];
closed = true;
createPath(vertices,inTangents,outTangents,closed);

[Dan Ebberts]

This version might be better--it's centered at the anchor point:

r = 100; // radius
ratio = .5523;
t = r*ratio;
vertices = [[0,-r],[r,0],[0,r],[-r,0]];
inTangents = [[-t,0],[0,-t],[t,0],[0,t]];
outTangents = [[t,0],[0,t],[-t,0],[0,-t]];
closed = true;
createPath(vertices,inTangents,outTangents,closed);

[Ignatz Johnson Higham]

This is great. I clearly didn't pay close attention in my maths classes. But why is the ratio .5523?
Plus it's super fun to link both radius and ratio to sliders and play around with them.

[Dan Ebberts]

I think the actual formula is:

ratio = (Math.SQRT2 - 1)*(4/3);