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HELP, Why is this wrong, both should return a numeric value.

Explorer ,
Nov 29, 2023 Nov 29, 2023

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transform.zPosition = thisComp.layer("text_02").transform.zPosition + 12;

 

 

 

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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It looks OK--where have you applied the expression? Are you getting an error message?

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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If you have applied the expression to a layer that doesn't have position dimensions separated, it would need to be more like this:

z = thisComp.layer("text_02").transform.zPosition + 12;
[value[0],value[1],z]

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Explorer ,
Nov 29, 2023 Nov 29, 2023

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Same results Error can't return results in numeric value

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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Can you post a screen shot that shows the expression in the timeline and the error message?

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Explorer ,
Nov 29, 2023 Nov 29, 2023

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Adobe After Effects 2024 - I__Family_Little Butt_#1 - After Effects_Happy Holidays_edited.jpg

 My guess I am wrong, I know C##, and Visual Basic to me that should work. So don't laugh

 

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Explorer ,
Nov 29, 2023 Nov 29, 2023

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Actually to me the 1st post should have worked.  

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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You'll get that error if text_02 doesn't have separated dimensions for position. If that's the case, this should work:

 

z = thisComp.layer("text_02").transform.position[2] + 12;
[value[0],value[1],z]

 

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Explorer ,
Nov 29, 2023 Nov 29, 2023

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Maybe I should tell you what I am looking for. I need an expression that moves layers below on the z axis a  # of pixels Hope that makes sense.

 

Thank

Mark

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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If neither layer has dimensions separated, the last one I posted should do the trick.

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Community Expert ,
Nov 29, 2023 Nov 29, 2023

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If you just want to move a layer a number of pixels in the z direction, something like this should work:

n = 12;
value + [0,0,n]

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