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Math sin expression problem-2

Engaged ,
Sep 26, 2024 Sep 26, 2024

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Hi,

 

I need some guidance from seniors here. If my AE comp height 1080, That means my Y axis limit is from 0 t0 1080. Right? that means My Sin wave's crest/peek will touch only two borders/egdes up and down where in Y axis down is 0 pixel and up is 1080. Then why the sin wave crossing the top/up edge here?? I already told the AE that value is 1080 in expression. then why its not listeing to the expression? When I specify the value in 'Expression' , the property that is linked to the expression must listen to that right? Please help me.

 

Square's Y position must stay between 0 and 1080, I mean it must only oscillate in between 0 and 1080, nowhere I said go beyong that. then why its going?

 

Red dots are where the crest/peek of the wave shud stay..Red dots are where the crest/peek of the wave shud stay..

 

 

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Error or problem , Expressions

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correct answers 1 Correct answer

Enthusiast , Sep 26, 2024 Sep 26, 2024

The value of sine oscillates between 1 and -1, so there is a difference of 2.

If you want a range of 1080, you need to oscillate between 540 and -540,

so something like:

 

Math.sin(time) * 540 + value

 

 

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Enthusiast ,
Sep 26, 2024 Sep 26, 2024

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The value of sine oscillates between 1 and -1, so there is a difference of 2.

If you want a range of 1080, you need to oscillate between 540 and -540,

so something like:

 

Math.sin(time) * 540 + value

 

 

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Engaged ,
Sep 26, 2024 Sep 26, 2024

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😮 😮 😮 You are so right. Thank you so much. 

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