Please help me!

[Mitesh Mhatre]

@Rick Gerard @Mylenium 

I'm trying to dynamically adjust keyframe values, & I'm pretty much successfull. but problem is after effects only catch one linear expression (first & second keyframe can be dynamically change) but not others. how to do that? please help.

[Mitesh Mhatre]

"Flow" is actually expression interpolation plugin for after effects: Click Here To See Flow Plugin 

bu the problem is when i tried custom easing it 's not catch due to Function is not function customBezier(t,tMin,tMax,value1,value2) it's 6 values > function customBezier(t,tMin,tMax,value1,value2,bezierPoints)  Now half of my problem is solved but half is still there: can you solve this?

/* ---------- Flow Function Declarations ---------- */
function customBezier(t,tMin,tMax,value1,value2,bezierPoints){if(arguments.length!==6)return value;var a=value2-value1;var b=tMax-tMin;var c=clamp((t-tMin)/b,0,1);if(!(bezierPoints instanceof Array)||bezierPoints.length!==4)bezierPoints=[0,0,1,1];return a*h(c,bezierPoints)+value1;function h(f,g){var x=3*g[0];var j=3*(g[2]-g[0])-x;var k=1-x-j;var l=3*g[1];var m=3*(g[3]-g[1])-l;var n=1-l-m;var d=f;for(var i=0;i<5;i++){var z=d*(x+d*(j+d*k))-f;if(Math.abs(z)<1e-3)break;d-=z/(x+d*(2*j+3*k*d));}return d*(l+d*(m+d*n));}}
/* ---------- Flow Function Declarations ---------- */
/* ---------- Flow Expression Template ------------ */
var animationStartTime = 1;
var animationEndTime = 2;
var startValue = value;
var endValue = value * 2;
if (numKeys > 0) {
var nearestKeyIndex = nearestKey(time).index;
if (key(nearestKeyIndex).time > time) nearestKeyIndex--;
if (nearestKeyIndex === 0 || nearestKeyIndex === numKeys) {
startValue = endValue = value;
} else {
animationStartTime = key(nearestKeyIndex).time;
animationEndTime = key(nearestKeyIndex + 1).time;
startValue = key(nearestKeyIndex).value;
endValue = key(nearestKeyIndex + 1).value;
}
}
customBezier(time, animationStartTime, animationEndTime, startValue, endValue, [0.9, 0, 0.56, 0.8]);
/* ---------- Flow Expression Template ------------ */

sliderControl = comp("Title 02").layer("Setting").effect("MF - Lines")(1);

if (numKeys > 1){
t1 = key(1).time;
t2 = key(2).time;
t3 = key(3).time;
t4 = key(4).time;
v1 = [25];
v2 = [40];
v3 = [50];
v4 = [70];
if (time < key(2).time)
customBezier(time, t1, t2, v1, v2); else customBezier(time, t2, t3, v2, v3);
if (time < key(3).time)
customBezier(time, t1, t2, v1, v2); else customBezier(time, t3, t4, v3, v4);
} else {
value
}

[Mitesh Mhatre]

@Dan Ebberts @Mathias Moehl 

[Dan Ebberts]

If you're going to use that function, you have to provide the 6th argument, which is a 4-element array that defines the x and  y coordinates of the two bezier handles. I'm guessing the coordinate system defines [0,0] as the start value and [1,1] as the end value, so I'd suggest you try [0.33, 0, 0.67, 1] and see what you get.

[Mitesh Mhatre]

Nope sir no help, I think we have to change function to customBezier(t,tMin,tMax,value1,value2) from customBezier(t,tMin,tMax,value1,value2,bezierPoints)

so can we change or alter function to another? I previously gave you "expo" expression. it's catching easing and all values because after effects default interpolation is limited to 3 or 5 but here in customBezier it's exceeds to 6 which is higher... so first we have to make it 5 values... we have to change function to 5 values only then custom Bezier will work i think!  It's very hard but I think you can do it... maybe.... 8)😁

[Dan Ebberts]

I don't see any way for the bezier calculation to work without specifying the handles...

[Mitesh Mhatre]

this code is given by you:

keyValues = [60,40,100,60];
val = value;
if (numKeys > 0){
  n = nearestKey(time).index;
  if (time < key(n).time) n--;
  if (n < 1){
    val = keyValues[0];
  }else if (n == numKeys){
    val = keyValues[keyValues.length-1];
  }else{
    v1 = keyValues[n-1];
    v2 = keyValues[n];
    val = ease(time,key(n).time,key(n+1).time,v1,v2);
  }
}
val

so my idea is if we crate a new layer & use try catch(err) method for catching all the key values and add flow plugin expression there? is it possible?

[Dan Ebberts]

I have no idea how try/catch would be useful in this situation...

[Mitesh Mhatre]

as you can see two keframes catching easing with values too! (It's limited to two keyframes only, don't know why!) 

So, now the only solution I have is to create same multiple layers & only set two keyframes. Simple! 😁

if want to add something new in this, it would be great... otherwise thank you for help me my brother... you all helps me a lot!!! 

[Mathias Moehl · Accepted solution]

oh, yes, I forgot  that Ae's linear behaves strange when linear(t,t1,t2,...)  t1 > t2.

Therefore, my expression only works if the value is increasing, not when it is going down.
Does this one work as expected for you?

keyValues = [60,40,100,60];

function myLinear(t,tMin,tMax,vMin,vMax) {
if(tMax< tMin){
var temp = tMax;
tMax=tMin;
tMin=temp;
temp=vMax;
vMax=vMin;
vMin=temp;
}
var result = vMin;
if(tMin==tMax){
result = vMin;
}
else {
result= vMin+( (t-tMin)/(tMax-tMin))*(vMax-vMin);
}
return result;
}

val = value;
if (numKeys > 0){
n = nearestKey(time).index;
if (time < key(n).time) n--;
if (n < 1){
val = keyValues[0];
}else if (n == numKeys){
val = keyValues[keyValues.length-1];
}else{
v1 = keyValues[n-1];
v2 = keyValues[n];
val = myLinear(value,key(n).value,key(n+1).value,v1,v2);
}
}
val

[Mitesh Mhatre]

Yes, this works as expected!!! Thank You very much all my teachers!!!! @Mathias Moehl  @Dan Ebberts  @Mylenium   

& Wish you all Happy Holi.... Today in our India, we are celebrating "Holi" The festival of colors....

May god KRISHNA give you long life, prosperity, wealth, health & all... 🙂 

[Mathias Moehl]

You are welcome 🙂