scale up and down expression

[chrisb50710065]

Hi,

I'm looking to create an expression that does the same as this opacity expression, which fades in and out, but for scale

fadeInTime = .15; // fade in time (seconds)

fadeOutTime = .15;

Math.min(linear(time,inPoint,inPoint +

fadeInTime,0,100),linear(time,outPoint -

fadeOutTime,outPoint,100,0))

I've tried this but it doesn't work.

fadeInTime = .15;// fade in time (seconds)

fadeOutTime = .15;

Math.min(linear(time,inPoint,inPoint +

fadeInTime,[0,0],[100,100]),linear(time,outPoint -

fadeOutTime,outPoint,[100,100],[0,0]))

this works on it's own for the in but i can't make it work for the out!!

fadeInTime = .15;// fade in time (seconds)

fadeOutTime = .15;

linear(time,inPoint,inPoint +

fadeInTime,[0,0],[100,100])

Can you help?

Thanks

Chris

[Dan Ebberts · Accepted solution]

This should work:

fadeInTime = .15;

fadeOutTime = .15;

if (time < (inPoint+outPoint)/2){

  linear(time,inPoint,inPoint+fadeInTime,[0,0],[100,100]);

}else{

  linear(time,outPoint-fadeOutTime,outPoint,[100,100],[0,0]);

}

Dan

[chrisb50710065]

Thank you, thank you,

Where was I going wrong?  is it easy to explain?

[Dan Ebberts]

The method that you were using relies on a Math.min()  trick that works with single values varying between 0 and 100, but not with arrays, like scale values. You could make that method work like this though:

fadeInTime = .15;

fadeOutTime = .15;

s = Math.min(linear(time,inPoint,inPoint + fadeInTime,0,100),linear(time,outPoint - fadeOutTime,outPoint,100,0));

[s,s]

Dan

[chrisb50710065]

Thanks.